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无马拐角和数独(入门级) https://gridpuzzle.com/anti-knight-vudoku/3jjg1

#3jjg1的最新成绩列表

gu
guest há um segundo
11'11''
re
recovery 6 minutos atrás
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in
injury 19 minutos atrás
6'20''
El
Elijah 40 minutos atrás
13'16''
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phone há uma hora
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gu
guest há uma hora
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Liam há uma hora
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an
anonymous 55 minutos atrás
15'21''
gu
guest 2 horas atrás
12'29''
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Elijah 2 horas atrás
5'23''

无马拐角和数独的最新成绩列表

an
anonymous 完成 题ID#6n2g5;
19'20''
Ja
James 完成 题ID#k8564;
12'6''
re
recovery 完成 题ID#zq8mr;
6'52''
gu
guest 完成 题ID#g4ggm;
14'54''
an
anonymous 完成 题ID#k8564;
9'18''
bu
business 完成 题ID#7pzwj;
3'42''
gu
guest 完成 题ID#zvrjn;
12'25''
Ol
Olivia 完成 题ID#82nxx;
11'28''
Em
Emma 完成 题ID#zq8mr;
4'33''
fr
freelance 完成 题ID#dn6m0;
10'42''

如何玩无马拐角和数独

无马拐角和数独规则

  • 将1~9填入空格内,使行、列及九宫格内均无重复数。

  • 每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。

  • 非全标。

  • 无马规则:任意数字与其马步格数字不重复

拐角数独,每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。 非全标。

无马拐角和数独 = 拐角和数独 + 无马数独

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