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无马拐角和数独(骨灰级) https://gridpuzzle.com/anti-knight-vudoku/r8224

#r8224的最新成绩列表

gu
guest há um segundo
3'37''
re
restoration 18 minutos atrás
10'33''
sp
specialist 27 minutos atrás
5'0''
an
anonymous 54 minutos atrás
6'24''
in
injury 15 minutos atrás
10'8''
No
Noah 46 minutos atrás
9'12''
be
beauty há uma hora
13'43''
an
anonymous 44 minutos atrás
9'52''
te
teriyaki 2 horas atrás
7'45''
an
anonymous há uma hora
12'20''

无马拐角和数独的最新成绩列表

gu
guest 完成 题ID#q854e;
15'57''
gu
guest 完成 题ID#we0pk;
15'49''
gu
guest 完成 题ID#4w8v8;
16'36''
gu
guest 完成 题ID#pw4rr;
14'35''
ma
masters 完成 题ID#dpqz7;
11'56''
an
anonymous 完成 题ID#4w8v8;
19'45''
an
anonymous 完成 题ID#vr9jy;
19'14''
El
Elijah 完成 题ID#4w8v8;
14'37''
da
damage 完成 题ID#rm75j;
15'59''
re
repair 完成 题ID#4w8v8;
5'23''

如何玩无马拐角和数独

无马拐角和数独规则

  • 将1~9填入空格内,使行、列及九宫格内均无重复数。

  • 每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。

  • 非全标。

  • 无马规则:任意数字与其马步格数字不重复

拐角数独,每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。 非全标。

无马拐角和数独 = 拐角和数独 + 无马数独

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