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无马拐角和数独(高级) https://gridpuzzle.com/anti-knight-vudoku/rmr61

#rmr61的最新成绩列表

gu
guest há um segundo
4'52''
an
anonymous 14 minutos atrás
11'50''
pe
petrol 25 minutos atrás
9'42''
ma
makeup 54 minutos atrás
18'38''
gu
guest 56 minutos atrás
16'36''
Re
Recovery 20 minutos atrás
8'26''
an
anonymous há uma hora
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injury há uma hora
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Mi
Mia 2 horas atrás
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Paintless 2 horas atrás
12'19''

无马拐角和数独的最新成绩列表

gu
guest 完成 题ID#n2xpx;
16'51''
an
anonymous 完成 题ID#4wn04;
13'31''
se
sell cash 完成 题ID#16yk9;
18'46''
an
anonymous 完成 题ID#4wn04;
16'53''
an
anonymous 完成 题ID#xzj87;
5'18''
an
anonymous 完成 题ID#zqgnm;
11'34''
an
anonymous 完成 题ID#kdmnq;
14'50''
so
software 完成 题ID#wrn7y;
14'27''
da
damage 完成 题ID#k85m1;
11'17''
an
anonymous 完成 题ID#xzj87;
4'55''

如何玩无马拐角和数独

无马拐角和数独规则

  • 将1~9填入空格内,使行、列及九宫格内均无重复数。

  • 每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。

  • 非全标。

  • 无马规则:任意数字与其马步格数字不重复

拐角数独,每个拐角(弯三)的格子中(灰色的折线)必有有2个数加起来等于另一个数,但无顺序要求。 非全标。

无马拐角和数独 = 拐角和数独 + 无马数独

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